line in 16A - Slovinia
Question
correctly or .... the line in 16A ...and input toroid 3A ....? tx http://img13.imageshack.us/img13/3582/linein16a.png |
That looks correct to me. 500W ~= 500VA / 220V = 2.27A so 3A is reasonable. 16A - 3A = 13A left over to provide to your spindle.
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honestly,
many do not putting 16A the fuse .. I watched the making, do not put either 16A or 3A :confused: |
Well one reason is the feed line has breaker typically.
I would put that 16a breaker after the disconnect. I also question the 3 amp fuse size or need. |
..after the disconnect?
I do not know where exactly you think! |
...finally I do not need any fuses!
greeting |
A fuse is much cheaper than anything in the whole control box. They are there to save you money in the long run.
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I can understand fuses in the right places. They are needed. Typically in the PS these are on the output side of the PS. On the input side we have breakers. That is what I am talking about.
What I see in the drawing above is that line in voltage comes in through a breaker into a rotary disconnect switch and then through a fuse. The other leg is not connected to a fuse or breaker. If that is a Neutral line I can understand that setup with the exception of the 3A fuse. IF your fusing it at that point in the line, my question (I Iam not an electrician) is : Is that fuse large enough? My other comment before was IF that is a 220V (Two 110V feeds) setup and we assume the feeder voltages are coming from a circuit with a breaker. I would have that breaker AFTER the rotary disconnect AND I would have a double pole breaker of the desired amperage to protect the transformer. And after saying that last part out loud, not a bad thought for everyone to do that. I hope I am making sense with that. |
hello.
Again, I had to clarify this question ... I asked my friend *professional electrician*. answer is shown below.... http://img9.imageshack.us/img9/9130/revyv.jpg or like the drawing 1070230 :D greeting |
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